Question

sec^-1(1)=??????????????​

Answer 1

Answer: sec^-1(1)= 0

Step-by-step explanation:(I am using 'Q' as theta)

sec^-1(x)= Q, IxI ≥ 1

So, sec Q = x ,Q ∈  [ 0 , π ] −  { π/ 2 }

Since sec 0=1, where   0 ∈  [ 0 , π ] −  { π/ 2 }  , we have sec^-1(1)= 0

Hope this helps........