sec^(-1)2x - 3sin^(-1)X + cos^(-1) (x²) (differentiation)
Answers
Step-by-step explanation:
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▪Given :-
The internal angles of a quadrilateral are
x, x + 30°, x + 60 and 4x
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▪To Calculate :-
The difference between greatest angle and the smallest angle.
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▪Key Concept :-
☆《Angle Sum Property》
The sum of internal angles of any quadrilateral is
360°.
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▪Solution :-
As
1st angle = x
2nd angle = x + 30°
3rd angle = x + 60°
4th angle = 4x
According to Angle Sum Property :-
x + x + 30° + x + 60° + 4x = 360°
⟹ 7x + 90° = 360°
⟹ 7x = 270°
\implies\boxed{\underline{\red{ \large \mathfrak{x = \bf \frac{270}{7} }}}}⟹x=7270
So,
1st angle = 270°/7
2nd angle =270°/7+ 30° = 480°/7
3rd angle = 270°/7 + 60° = 690°/7
4th angle = 4 × 270°/7 = 1080°/7
Now,
The difference between greatest angle and the smallest angle = 1080°/7 - 270°/7
= 810°/7
\begin{gathered}\red{\Large\mathfrak{ \text{W}hich \: \: is \: \: the \: \: required}}\\\red{ \huge\mathfrak{ \text{ A}nswer.}}\end{gathered} Which is the required Answer.
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