Question

sec^-¹√5+1/2 sin^-¹4/5-sin^-¹1/√5=tan^-¹2

Answer 1

Answer:

LHS = sin - 1 4 5 + 2 tan - 1 1 3 = sin - 1 4 5 + tan - 1 { 2 × 1 3 1 - ( 1 3 ) 2 } [ ∵ 2 tan - 1 x = tan - 1 { 2 x 1 - x 2 } = sin - 1 4 5 + tan - 1 { 2 3 8 9 }

Missing: sec^- ‎| Must include: sec^-

Answer 2

Answer:

sorry brother don't known