Math, asked by aakashkumawat6p2wsx6, 1 year ago

√sec+1/sec-1=cot+cosec


Ankitsuraj: hey i am not able to understand your question. is there whole under root or just sec-1
aakashkumawat6p2wsx6: this is all in under root from root to equal sign
Ankitsuraj: okay then i will solve it just wait
Ankitsuraj: let watch

Answers

Answered by Ankitsuraj
3
first of all you have to rationalize the LHS
after some steps you will get
 \sqrt{(sec + 1) {}^{2} }  \div  \sqrt{sec {}^{2} - 1 }
sec2-1 =tan2
then u get
sec + 1 \div tan
after removing root
you have to separate it as
sec \div tan + 1 \div tan

at last u get
sec/tan=cosec
1/tan = cot

Ankitsuraj: is it helpful
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