Question

√sec+1/sec-1=cot+cosec

Answer 1

root (sec+1)/root(sec-1)
= root (sec+1) root (sec-1)/root (sec-1) root (sec-1)
= root (sec^2-1)/(sec-2)
= root(1-1/sec^2)/(1-1/sec)
= root(1-cos^2)/(1-cos)
=sin /1-cos
= sin (1+cos) / (1-cos)(1+cos)
= sin (1+cos)/(1-cos^2)
= sin (1+cos)/sin^2
= (1+cos)/sin
= 1/ sin+cos /sin
= cosec+ cot
= cot +cosec