Question

√sec-1/sec +1 = sec-tan
prove
LHS=RHS​

Answer 1

I think this is answer

and see you question properly

Answer 2

$\sqrt{ \frac{sec - 1}{sec + 1} } \\ \\ = \sqrt{ \frac{1 - cos}{1 + cos} } \\ \\ = \sqrt{ \frac{ 1 - cos}{1 + cos} \times \frac{1 - cos}{1 + cos} } \\ \\ = \sqrt{ \frac{( {1 - cos)}^{2} }{1 - {cos}^{2} } } \\ \\ = \sqrt{ \frac{( {1 - cos})^{2} }{ {sin}^{2} } } \\ \\ = \frac{1 - cos}{sin} \\ \\ = cosec - cot$