Question

secθ √1-sin^θ=1
pls tell me a proper aanswer
if you give inappropriate answer
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Answer 1

$\huge\tt{\red{Given:}}$

★$sec\theta \sqrt{1-sin^{2}\theta}=1$

$\huge\tt{\red{To\:\:Prove}}$

★LHS=RHS

$\huge\tt{\red{Answer}}$

We have

LHS

= $sec\theta \sqrt{1-sin^{2}\theta}$

=$sec\theta \sqrt{cos^{2}\theta}$

$\large\green{\boxed{sin^{2}\theta + cos^{2}\theta=1}}$

=$sec\theta \times cos\theta$

=$\cancel{sec\theta} \times \dfrac{1}{\cancel{sec\theta}}$

$\large\purple{\boxed{sec\theta=\dfrac{1}{cos\theta}}}$

=1

RHS = 1

. °. LHS = RHS

Hence proved.

Answer 2

Step-by-step explanation:

♥ LHS is equal to RHS.............