Math, asked by ujjwaljoshipusa, 5 months ago

sec^-1 [x^2+1 /x^2-1]=


Answers

Answered by bourai244
0

Step-by-step explanation:

sec^-1[ x^2 +1/x^2-1]

= sev^-1 [ 1+ tan^2x/ -(1- tan^2x)]

= sec^-1 {1+tan^2x/ 1-tan^2x}

= sec^-1{ sec 2x}

= 2x

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