Math, asked by paramsaggu213, 11 months ago

sec 10×sec 10- cot 80×cot 80+ 1

Answers

Answered by flamebysis1782

0

Answer:

sec(10)6-cot(80)6+1

Step-by-step explanation:

sec(10)^-cot(80)cot(80)+1

sec(10)^-cot(80)6+1

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