sec 16°×cosec 74°- cot 74°×tan 16°
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Answered by
8
Answer:
sec16*cosec74-cot74*tan16
sec16*sec(90-16)-cot74*(90-74)*tan16
sec16*sec16-tan16*tan16=1*1=1
Step-by-step explanation:
Answered by
5
Step-by-step explanation:
Sec16.cosec74 - cot74.tan16
=cosec74.cosec74 - cot74.cot74
=cosec^2 (74) - cot^2(74)
= 1
(1 + cot^2 Q = cosec^2 Q)
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