Biology, asked by saimohith18, 10 months ago

sec 16° cosec 74º- cot 74º tan 16º.​

Answers

Answered by bhavya12095
10

Answer:

1

Explanation:

sec16°cosec74°-cot74°tan16°

=sec(90-74)cosec74°-cot(90-16) tan16°

=cosec74°cosec74°-tan16°tan16°

=(cosec74°)^2-(tan16°)^2

=1

Similar questions