sec 16° cosec 74º- cot 74º tan 16º.
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10
Answer:
1
Explanation:
sec16°cosec74°-cot74°tan16°
=sec(90-74)cosec74°-cot(90-16) tan16°
=cosec74°cosec74°-tan16°tan16°
=(cosec74°)^2-(tan16°)^2
=1
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