Sec(-1680)Sin(330)=1
Answers
Answered by
17
Hi Friend !!!
Here is ur answer !!!
sec(1680)sin330
= sec(1440+240)sin(360-30)
= sec240sin-30
= - sec(270-30)sin30
= cosec 30 sin30
= sin30/sin30
= 1
Hope it helps u :-)
Here is ur answer !!!
sec(1680)sin330
= sec(1440+240)sin(360-30)
= sec240sin-30
= - sec(270-30)sin30
= cosec 30 sin30
= sin30/sin30
= 1
Hope it helps u :-)
Answered by
15
Answer:
The proof is explained step-wise below :
Step-by-step explanation:
To Prove : sec(-1680) × sin(330) = 1
Proof : Taking L.H.S
sec(-1680) × sin(330)
⇒ sec(1680) × sin(330) (∵ sec(-α) = sec α)
⇒ sec (1440 + 240) × sin(360 - 30)
⇒ -sec(240) × -sin 30°
⇒ sec(270 - 30) × sin 30°
⇒ cosec 30° × sin 30°
⇒ 1
= R.H.S.
Hence Proved
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