(sec ^2 Ѳ – 1) (cosec ^2 Ѳ - 1 ) = 1
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tan^2A(cot^2A)=1 is the answer I hope this helps you
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let us assume theta as ○
by solving LHS
(sec^2○ - 1) ( cosec^2○ - 1)
we know that 1 + tan2○ = sec^2 ○
tan^2○=sec^2○-1
we also know that
1 + cot^2○ = cosec^2○
cot^2○ = cosec^2○-1
as per the problem
tan^2○×cot^2 ○ = 1
RHS = 1
HENCE PROVED
hope it helps
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