Math, asked by Abhijitdehury1905, 5 hours ago

sec^2(105°+a)-tan^2(75°-a)​

Answers

Answered by Anonymous
5

Step-by-step explanation:

sec²(105+a) -tan²(75-a)

sec²(105+a) -tan²(180-(105+a))

sec²(105+a) -[-cot²(90-(105+a) ]

sec²(105+a) -tan²(105+a)

1

1 is the answer

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