Question

sec^2+ 4 sec θ − 5 = 0

Answer 1

Answer:

sec^2 + 4 sec theta -5 = 0

you can clearly see that it is in a quadratic form which is ax^2 + bx + c = 0

let sec theta = x

x^2 + 4x - 5 = 0

x^2 + 5x - x - 5 = 0

x(x+5)-1(x+5)=0

(x-1)(x+5) = 0

x - 1 = 0                         x + 5 = 0

x = 1                               x = -5

sec theta = 1                  (not possible because sec theta's value can't be -ve)

sec theta = sec 0

theta = 0

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