Math, asked by Powermania9918, 1 year ago

sec^2 65 - cot^2 25 -2sin30 cos60

Answers

Answered by wwwyashbikashrina
1

Answer:

See the pic below

Answered by divyanjali714
1

Concept:

We need to know few trigonometric equtions like the below:

If Cot x= Cot(90-y), then Cot x=Tan y

sec^{2}x- tan^{2}x=1

Sin30=\frac{1}{2} \ and\ cos60= \frac{1}{2}

Given:

The following trigonometric equation is given:

sec^{2}65-cot^{2} 25-2sin30cos30

To find:

We need to find the value of the given equation.

Solution:

Now, we know that

25°=90°-65°

Then

cot25=cot(90-65)\\

cot25=tan65

Therefore

sec^{2}65-tan^{2} 65-2sin30cos30

1-2(\frac{1}{2})(\frac{1}{2} )             [sec^{2}x- tan^{2}x=1]

1-\frac{1}{2}

\frac{1}{2}

Therefore the value  of the trigonometric equation is \frac{1}{2}

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