Question

sec 2 a =cosec ( a - 42 ) where to a is an acute angle find the value of a. trigonometry chapter​

Answer 1

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here your answer...

sec2A=cosec (A-42°)

cosec(90°-A) =cosec (A-42°)

90-A=A-42

2A = 132

A=66

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Answer 2

sec2A=cosec (A-42°)

cosec(90°-A) =cosec (A-42°)

90-A=A-42

2A = 132

A=66

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