sec^2 A-cosec^A = sec^2•cosec^2
Answers
Answered by
2
Here it is
Take L.H.S
= Sec^2 A+ Cosec^ A
=1/Cos^2 A + 1/Sin^2 A
= (Cos^2 A+Sin^2 A)/Sin^2 A.Cos^2 A
= 1/Sin^2 A. Cos^2 A (As Sin^2 A + Cos^2 A = 1)
or you can write as
= 1/Sin^2 A . 1/Cos^2 A
which is Cosec^2 A.Sec^2 A which is same as Sec^2 ACosec^2A==>R.H.S
Hence Proved...
Take L.H.S
= Sec^2 A+ Cosec^ A
=1/Cos^2 A + 1/Sin^2 A
= (Cos^2 A+Sin^2 A)/Sin^2 A.Cos^2 A
= 1/Sin^2 A. Cos^2 A (As Sin^2 A + Cos^2 A = 1)
or you can write as
= 1/Sin^2 A . 1/Cos^2 A
which is Cosec^2 A.Sec^2 A which is same as Sec^2 ACosec^2A==>R.H.S
Hence Proved...
Similar questions
Math,
8 months ago
Social Sciences,
8 months ago
Environmental Sciences,
1 year ago
Physics,
1 year ago
Chemistry,
1 year ago