Math, asked by ramandeephagnahati, 6 months ago

sec^2 A - tan^2 A=1-sec A + tan A​

Answers

Answered by anushkasrivastava12O
1

Answer:

1=1

Step-by-step explanation:

sec^2A-tan^2A=1-secA+tanA

(sec^2A-tan^2A)=1-secA+tanA

1=1-secA-tanA

1=secA-tanA

1=1/cosA-sinA/cosA

1=1-sinA/cosA

1=1-sin^2A/cos^2A     (By squaring both side)

1=cos^2A/cos^2A

1=1

proved

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Answered by saiyedfazil
2

Sec^2A-tan^2A=1-secA+tanA

1/cos^2A - sin^2A/cos^2A = 1-secA+tanA

1-sin^2A/cos^2A = 1-secA+tanA

1-secA+tanA = 1-secA+tanA

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