sec^2 A + tan A = 13 then tan A = ??
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hope this helps u
we know that
sec²A-tan²A=1
⇒sec²A= 1 +tan²A-------(1)
sec²A+tanA= 13
1 +tan²A+tanA = 13 by using 1
tan²A+tan A = 13-1
tan²A+tan A= 12
tan²A+tan A-12=0
tan²A+4tan A-3tanA-12
tan A(tan A+4) -3(tanA+4)
(tan A+4) = 0 (tan A-3)=0
tan A = -4,3
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