sec^2+tan^2=5/3
please help me in this!!!
Answers
Answered by
1
Answer:
3(sec
2
θ+tan
2
θ)=5⇒tan
2
θ+1+tan
2
θ=
3
5
⇒2tan
2
θ+1=
3
5
⇒tan
2
θ=
3
1
=(
3
1
)
2
=(tan
6
π
)
2
⇒tanθ=±tan
6
π
⇒θ=nπ±
6
π
Answered By
Similar questions