Question

sec^2-tan^2Q+tanQ cotq=?

Answer 1

Answer:

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Answer 2

$Given \: Sec^{2} Q - tan^{2} Q + tan Q Cot Q \\= 1 + 1$

/* We know that */

$\blue { 1) Sec^{2} Q - tan^{2} Q = 1 }$

$\blue { 2) tan Q Cot Q = 1 }$

$= 2$

Therefore.,

$\red{ Sec^{2} Q - tan^{2} Q + tan Q Cot Q }\green { = 2 }$

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