Question

sec^2 teta+ sec teta=6 then find teta

Answer 1

sec²∅ + sec∅ = 6

sec²∅ + sec∅ - 6 = 0

sec²∅ + ( 3 - 2 ) sec∅ - 6 = 0

sec²∅ + 3 sec∅ - 2 sec∅ - 6 = 0

sec∅( sec∅ + 3 ) - 2( sec∅ + 3 ) = 0

( sec∅ + 3 )( sec∅ - 2 ) = 0



$\: \: \: \: \: \: \: By \: \: Zero \: \: Pr oduct \: \: Rule,$


sec∅ = - 3
Or, sec∅ = 2


Taking positive value,sec∅ = 2


sec∅ = 2

sec∅ = sec60

∅ = 60




Therefore, value of theta is 60°