Question

sec^2 theta + cosec^2 theta = sec^2 theta × cosec^2 theta
it's urgent!!!!​

Answer 1

$Sec²O + Cosec²O$

$\frac{1}{Cos²O} + \frac{1}{Sin²O}$

$\frac{(Sin²O + Cos²O)}{Cos²O*Sin²O}$

$\frac{1}{Cos²O*Sin²O}$

$\frac{1}{Cos²O} × \frac{1}{Sin²O}$

$Sec²O*Cosec²O$