Question

sec ^2 x-cosec squared x / tan squared x minus cot squared x​

Answer 1

Answer:

1

Step-by-step explanation:

PUT tan² θ + 1 = sec² θ  and   cot² θ + 1 = cosec² θ

[tan²x + 1 - (cot²x + 1)] / (tan²x - cot²x)

[tan²x - cot²x + 1 - 1] / (tan²x - cot²x)

[tan²x - cot²x]  / (tan²x - cot²x)

= 1

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