Math, asked by aditimadaan14, 8 months ago

sec(270-theta)sec(theta-450)+tan(450+theta)tan(theta-270)​

Answers

Answered by pulakmath007
3

SOLUTION

TO DETERMINE

The value of

sec(270° - θ )sec(θ-450°) + tan(450°+θ)tan(θ-270°)

EVALUATION

Here the given expression is

sec(270° -θ )sec(θ-450°)+tan(450°+θ)tan(θ-270°)

We simplify it as below

sec(270° - θ )sec(θ-450°)+tan(450°+θ)tan(θ-270°)

= sec(270° - θ )sec(450°-θ) - tan(450°+θ)tan(270°-θ)

= - sec θ sec θ - ( - tan θ ) tan θ

= - sec² θ + tan² θ

= - 1

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