(sec^2A-1)(cos^2A-1)=?
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Answered by
1
sec²A-1=tan²A
cos²A-1=sin²A
tan²A*-sin²A=
-sin⁴A/cos²A
# A student of class 10.
#Hope it helps.
# Smritu.
cos²A-1=sin²A
tan²A*-sin²A=
-sin⁴A/cos²A
# A student of class 10.
#Hope it helps.
# Smritu.
Anonymous:
no it's right... actually I missed out cos... but now I verified my mistake
do it again please
I edited my answer... now its error free.. the answer is now totally reliable
thanks a lot
Well sorry for the mistake I did prev
previously
Answered by
1
Using identites 1+tan^2A=Sec^A and sin^2A+cos^2A=1
We get tan^2A×(-sin^2A)=-sin^4A/cos^2A
Cheers. Brainliest mark me.
We get tan^2A×(-sin^2A)=-sin^4A/cos^2A
Cheers. Brainliest mark me.
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