Math, asked by harpreethkaurr, 1 day ago

sec^2A[1-sin^2A]+cot^2A=?

Answers

Answered by adiharshithaakuleti

0

Answer:

sec^2A×cos^2A+cot^2A. [1-sin^2A=cos^2A]

sec^2A×1/sec^2A+cot^2A. [cos^2A=1/sec^2A]

1+cot^2A

=cosec^2A. ['1+cot^2A=cosec^2A]

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