sec^2A + cosec^2A =sec^2A cosec^2A
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Answered by
6
hey friend ,
hers is your answer,
1/cos²a+1/Sin²a
(Sin²a+cos²a)/sin²a*cos²a
1/(sin²a*cos²a)
=cosec²a sec²a
=rhs
hope it helps you...!
hers is your answer,
1/cos²a+1/Sin²a
(Sin²a+cos²a)/sin²a*cos²a
1/(sin²a*cos²a)
=cosec²a sec²a
=rhs
hope it helps you...!
Answered by
1
This is the correct answer mark it as brainliest answer
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