Math, asked by preetiradhagiri, 10 months ago

√sec^2A + cosec^2A=tan A+cotA​

Answers

Answered by Anonymous
0

Answer:

Step-by-step explanation:

From LHS,

=>√1+tan^2A+1+cot^2A

=>√2+tan^2A+cot^2A

[tan^2A+cot^2A+2×tanA×cotA=tan^2A+cot^2A+2=(tanA+cotA)^2]

=>√(tanA+cotA)^2

=>tanA+cotA

LHS=RHS proved

Answered by heemani26
0

Answer:

Step-by-step explanation:

From LHS,

=>√1+tan^2A+1+cot^2A

=>√2+tan^2A+cot^2A

[tan^2A+cot^2A+2×tanA×cotA=tan^2A+cot^2A+2=(tanA+cotA)^2]

=>√(tanA+cotA)^2

=>tanA+cotA

LHS=RHS proved

Mai please please mark it as brainliest answer

Step-by-step explanation:

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