√sec^2A + cosec^2A=tan A+cotA
Answers
Answered by
0
Answer:
Step-by-step explanation:
From LHS,
=>√1+tan^2A+1+cot^2A
=>√2+tan^2A+cot^2A
[tan^2A+cot^2A+2×tanA×cotA=tan^2A+cot^2A+2=(tanA+cotA)^2]
=>√(tanA+cotA)^2
=>tanA+cotA
LHS=RHS proved
Answered by
0
Answer:
Step-by-step explanation:
From LHS,
=>√1+tan^2A+1+cot^2A
=>√2+tan^2A+cot^2A
[tan^2A+cot^2A+2×tanA×cotA=tan^2A+cot^2A+2=(tanA+cotA)^2]
=>√(tanA+cotA)^2
=>tanA+cotA
LHS=RHS proved
Mai please please mark it as brainliest answer
Step-by-step explanation:
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