Math, asked by shrui7755, 1 year ago

√( sec^2A + cosec^2A )= tanA + cot A

Answers

Answered by adee1729
11
√(1/cos²A + 1/sin²A),

√[(sin²A+cos²A)/sin²A.cos²A],

√(1/sin²A.cos²A),

1/sinA. cosA,

(sin²A+cos²A)/sinA.cosA,

sin²A/sinA.cosA + cos²A/sinA.cosA,

sinA/cosA + cosA/sinA,

tanA + cotA,

L.H.S = R.H.S

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