Sec^2A -cot^2 [90-A]=cos^2[90-A]+cos^2A
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cot^2(90-A)=tan^2A
therefore it becomes sec^2A-tan^2A=1.....(1)
cos^2(90-A)=sin^2A
so it becomes sin^2A+cos^2A=1....(2)
from (1) & (2)
hence proved.
if u like it mark it as brainliest answer.
therefore it becomes sec^2A-tan^2A=1.....(1)
cos^2(90-A)=sin^2A
so it becomes sin^2A+cos^2A=1....(2)
from (1) & (2)
hence proved.
if u like it mark it as brainliest answer.
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