sec^2A-tan^2A/cotA+tanA
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Step-by-step explanation:
Given,
sec²A-tan²A/cotA+tanA
Now,
= [(1/cos²A)-(sin²A/cos²A)]/[(cosA/sinA)+
(sinA/ cosA)]
= [1-sin²A/cos²A]/[cos²A+sin²A/sinA.cosA]
= (cos²A/cos²A)/(1/sinA.cosA)
= (1)/(1/sinA.cosA)
= 1/sinA.cosA
= 1/sinA . 1/cosA
= cosecA . secA
:. sec²A-tan²A/cotA+tanA = cosecA.secA.
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