Math, asked by ajjose845, 1 year ago

sec^2theta(1+ sin theta)(1-sin theta)=k,find the value of k

Answers

Answered by Hasti152002
3
Sec2 theta (1+sin)(1-sin)=k
Sec2theta *1-sin2 theta =k
Sec2theta *cos2 theta =k
K=1

Hope it helps you dear.........
Answered by Anonymous
4

Hey


The question is :-


Sec²∅ ( 1 + Sin∅ ) ( 1 - Sin∅ ) = K


= Sec²∅ [ ( 1 ) ² - ( Sin∅ )² ]


= Sec²∅ ( 1 - sin²∅ )


= sec²0 * cos²∅


= 1 / cos²∅ * cos²∅


= 1


So ,


k = 1


thanks :)
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