sec^2theta(1+ sin theta)(1-sin theta)=k,find the value of k
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Answered by
3
Sec2 theta (1+sin)(1-sin)=k
Sec2theta *1-sin2 theta =k
Sec2theta *cos2 theta =k
K=1
Hope it helps you dear.........
Sec2theta *1-sin2 theta =k
Sec2theta *cos2 theta =k
K=1
Hope it helps you dear.........
Answered by
4
Hey
The question is :-
Sec²∅ ( 1 + Sin∅ ) ( 1 - Sin∅ ) = K
= Sec²∅ [ ( 1 ) ² - ( Sin∅ )² ]
= Sec²∅ ( 1 - sin²∅ )
= sec²0 * cos²∅
= 1 / cos²∅ * cos²∅
= 1
So ,
k = 1
thanks :)
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