Math, asked by tanu1915, 1 year ago

sec^2theta×cosec^2theta=sec^2theta+cosec^2theta

Answers

Answered by shobaradkrish
3

LHS= 1/cos²∅ ×1/sin²∅

1/(cos∅×sin∅)²

RHS = 1/cos²∅+1/sin²∅

sin²∅+cos²∅/sin²∅×cos²∅

1/(sin+cos)²

LHS =RHS


shobaradkrish: SORRY THE LAST STEP IS 1/SIN2THETA *COS2THETA
shobaradkrish: mark me as the brainliest
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