sec^2theta×cosec^2theta=sec^2theta+cosec^2theta
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LHS= 1/cos²∅ ×1/sin²∅
1/(cos∅×sin∅)²
RHS = 1/cos²∅+1/sin²∅
sin²∅+cos²∅/sin²∅×cos²∅
1/(sin+cos)²
LHS =RHS
shobaradkrish:
SORRY THE LAST STEP IS 1/SIN2THETA *COS2THETA
mark me as the brainliest
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