Math, asked by trushna79, 7 months ago

sec^2theta=sec^2theta/√3​

Answers

Answered by tiwanasavitojs
1

Step-by-step explanation:

Simplifying 3sec2θ=2.

3sec2θ=2

23=sec2θ1

23=cos2θ

2θ=cos−1(23)

2θ=6π

θ=2nπ+12π

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