Question

sec^2thetha + cosec^2theta =​

Answer 1

$\large{\underbrace{\sf{\red{Correct\:Question:}}}}$

$\purple{\longrightarrow\:}$ $\rm{sec^{2}  \theta  + cosec^{2} \theta\: }$

$\large{\underline{\underline{\sf{\pink{Required\:Answer:}}}}}$

$\purple{\longrightarrow\:}$ $\rm{sec^{2}  \theta  + cosec^{2} \theta\: }$

$\purple{\longrightarrow\:}$ $\rm{\dfrac{1}{cos^{2} \theta } + \dfrac{1}{sin^{2} \theta}  }$

$\purple{\longrightarrow\:}$ $\rm{\dfrac{sin^{2} \theta +cos^{2}  \theta}{sin^{2}\theta\:cos^{2} \theta  } }$

$\purple{\longrightarrow\:}$ $\rm{\dfrac{1}{sin^{2} \theta \: cos^{2} \theta }  }$

$\rm{[Since\: sin^{2}   \theta + cos^{2} \theta = 1] }$

$\purple{\longrightarrow\:}$ $\rm{sec^{2} \theta.cosec^{2} \theta }$

______________________________________