Question

sec 30 + Cosec 45° / cos 30 - sin 30
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Answer 1

it would be sufficient answer

Answer 2

QUESTION:

TO FIND THE VALUE OF :-

• sec 30 + Cosec 45° / cos 30 - sin 30

FORMULAS USED:

$\sec(30) = \: 2\sqrt{3}$

$\cosec(45) = \sqrt{2}$

$\cos(30) = \sqrt{3} \div 2$

$\sin(30) = 1 \div 2$

ANSWER:

$now \: putting \: the \: values \\ \: according \: to \: the \: \\ order \: of \: the \: question \: we \: get$

$= 2\sqrt{3} + \sqrt{2} \div (\sqrt{ 3} - 1) \div 2$

$= (2 \sqrt{3} + \sqrt{2} )2 \div \sqrt{3} - 1$

$= 4\sqrt{3} + 2 \sqrt{2} \div \sqrt{3} - 1 \: \: \\ \\ (answer)$