sec 3x = -2 general solution?
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Answer
Correct option is
A
True
Given
cosx+cos3x+⋯+cosnx=
2sinx
sin2
n
x
LHS
cosx+cos3x+⋯+cosnx
Multipying and dividing by 2sinx
2sinx
2sinxcosx
+cos3x+⋯+cosnx
2sinx
sin2x
+cos3x+⋯+cosnx
2sinx
sin2x+2sinxcos3x
+⋯+cosnx
2sinx
sin2x+sin4x−sin2x
+⋯+cosnx
2sinx
sin4x
+cos5x+⋯+cosnx
⟹
2sinx
sin2
n−1
x
+cosnx
⟹
2sinx
sin2
n−1
x+2sinxcosnx
⟹
2sinx
sin2
n−1
x+sin2
n
x−sin2
n−1
x
⟹
sinx
sin2
n
x
RHS
Hence proved
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