Math, asked by lohitha2204, 1 year ago

Sec^4 A - Sec²A =tan^4A+tan^2 A​

Answers

Answered by prakrithi89
1

Step-by-step explanation:

LHS = sec^4A - sec^2A

taking common out

= sec^2A(sec^2A-1)

= (1+ tan^2A)(1+tan^2-1)

= (1+tan ^2A)×tan^2A

= tan^2A + tan^4A

Rearrange the terms we get

= tan^4A + tan ^2

I hope it will help you

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