Question

(sec 4 ø - sec 2 ø ) = tan 2 ø + tan 4ø​

Answer 1

${ \sec}^{4} - { \sec}^{2} \\ { \sec}^{2} ( { \sec }^{2} - 1) \\ (1 + { \tan }^{2} ) { \tan }^{2} \\ { \tan}^{2} + { \tan}^{4}$