Math, asked by Rihanashah, 1 month ago

sec^4 theeta - tan^4 theeta = 1 + 2tan^2 theeta​

Answers

Answered by ShiningBlossom
70

\bigstar\:\:\underline{\sf AnsWer :} \bigstar

 \sf \: sec^4  \theta - tan^4  \theta = 1 + 2tan^2  \theta

 \bf = L. H. S

 \sf \:  = sec^{4}  - tan^{4}

 \sf \: =  ( {sec}^{2}  \theta +  {tan}^{2} \theta)( {sec}^{2} \theta -  {tan}^{2} \theta)

 \sf \:  = (1 +  {tan}^{2} \theta +  {tan}^{2} \theta)

 \sf = (1 + 2 {tan}^{2} \theta)

 \bf \:  = R. H. S

ㅤㅤ

 \bf \: L. H. S= R. H. S

Answered by BrainlyQueer
2

Answer is in Attachment. . .

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