Math, asked by kunallonare9324, 1 year ago

sec(45°+a)sec(45°-a)=2sec2a

Answers

Answered by rinkydora5485
1

Step-by-step explanation:

sec(45°+a)sec(45°-a)

=1/cos(45°+a).1/cos(45°-a)

=1/cos^2(45°)- sin^2a

=1/1/2-sin^a

=2/1- 2sin^a

=2/cos2a

=2sec2a

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