Question

Sec 45° /sec 30°+ cosec 60°

Answer 1

Answer:

root2

Step-by-step explanation:

1. value of sec45=root2
2. value of sec30=2/root3
3. value of cosec60=2/root3

now

root2/ 2/root3+2/root3

then 2/root3 will get cancelled then root2 will be the answer

Answer 2

Step-by-step explanation:

Given : A trigonometric equation $\frac{sec45\°}{sec30\°} +cosec60\°$

To find : the value of given trigonometric equation.

Trigonometric values used :

1. $sec45\°=\sqrt2$
2. $sec30\°=\frac{2}{\sqrt3}$
3. $cosec60\°=\frac{2}{\sqrt3}$

• Calculation for equation

We have

⇒   $\frac{sec45\°}{sec30\°} +cosec60\°$

also we have the values of all trigonometric functions so by putting them we get the answer,

$sec45\°=\sqrt2$     ,      $sec30\°=\frac{2}{\sqrt3}$        and   $cosec60\°=\frac{2}{\sqrt3}$

⇒  $\frac{\sqrt2}{\frac{2}{\sqrt3} } +\frac{2}{\sqrt3}$

⇒  $\frac{\sqrt2*\sqrt3}{{2} } +\frac{2}{\sqrt3}$

taking L.C.M as $2\sqrt3$ ,

⇒  $\frac{\sqrt2*\sqrt3*\sqrt3+2*2}{2\sqrt3}$

⇒  $\frac{3\sqrt2+4}{2\sqrt3}$

Hence we get the answer as $\frac{3\sqrt2+4}{2\sqrt3}$.