Math, asked by aayushashrestha23, 22 days ago

sec^4a-1=tan^2a+tan^4a​

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Answered by Hellouhaz
1

Answer:

Here is your proof:

Step-by-step explanation:

sec^4a -1 = (sec^2a -1 )(sec^2a + 1)….    (a^2-b^2 factorization)

Now, we know,

sec^2x = tan^2x + 1

so above equation becomes

sec^4a -1 = (tan^2a )(tan^2a +1 + 1)

               = tan^2a (tan^2a +2)

               = 2tan^2a + tan^4a

Hence Proved

Answered by vimalkumarvishwakarm
1

Answer:

aapko is answer se help jarur Mili hogi

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