sec^4a-1=tan^2a+tan^4a
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Here is your proof:
Step-by-step explanation:
sec^4a -1 = (sec^2a -1 )(sec^2a + 1)…. (a^2-b^2 factorization)
Now, we know,
sec^2x = tan^2x + 1
so above equation becomes
sec^4a -1 = (tan^2a )(tan^2a +1 + 1)
= tan^2a (tan^2a +2)
= 2tan^2a + tan^4a
Hence Proved
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aapko is answer se help jarur Mili hogi
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