Sec 4A = cosec(A-20°); A=?
Answers
Answered by
8
Sec 4A = Cosec (A-20)
Sec4A = Sec [90-(A-20)]
[ since (sec90-A) = cosec A]
4A = [90-(A-20] {sec cancels with sec}
4A = 90 - A + 20
4A+ A = 110
5A = 110
A = 110/5
A = 22°
Hope it helps.
Sec4A = Sec [90-(A-20)]
[ since (sec90-A) = cosec A]
4A = [90-(A-20] {sec cancels with sec}
4A = 90 - A + 20
4A+ A = 110
5A = 110
A = 110/5
A = 22°
Hope it helps.
Answered by
1
Answer:
Step-by-step explanation:
sec4A=sec{90°-(A-20°)}
4A=90°+20°-A
4A+A=110°
5A=110°
A=110/5
A=22°
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