Math, asked by darkaknight0099, 9 months ago

sec^4A - tan^2A=tan^4A+sec^2A​

Answers

Answered by rizwan1
0

sec^4A =(sec^2A)^2 = (1+tan^2A)^2

(1+tan^2A)^2 - (tan A)^2 = 1 +2×tan^2A +tan^4A - tan^2A = 1+ tan^2A+tan^4A = sec^2A + tan^4A

Answered by Ravirajraja
0

Step-by-step explanation:

sec^4A - tan^2A = tan^4A +sec^2A

sec^4A -sec^2A = tan^4A + tan^2A

sec^2A (sec^2A-1)= tan^2A( tan^2A+1)

sec^2A× tan^2A = tan^2A × sec^2A

L. H. S = R. H. S

Hence Proved.

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