sec 50 sin 40+ los 40 cosec 50
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Answer:
Value of Sec50°sin40°+cos40°cosec50° = 2
Step-by-step explanation:
= sec(90°-40°)sin40°+cos40°cosec(90°-50°)
= cosec40°sin40°+cos40°sec40°
we know that,
i)sec(90°-A) = cosecA
ii) cosec(90°-A)=secA
= (1/sin40)xsin40+(cos40x1/cos40)
After cancelling, we get
= 1+1
= 2
Therefore,
Value of Sec50°sin40°+cos40°cosec50° = 2
Step-by-step explanation:
Answered by
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Answer:
Mark as brainliest friend
Step-by-step explanation:
Sec50°sin40°+cos40°cosec50°
[1/cos50°]sin40°+cos40°[1/sin50°]
[1/sin40°]sin40°+cos40°[1/cos40°]
1+1=*2*
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