Sec 50° + tan 50 is equal to
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10
Step-by-step explanation:
the solution is a bit tricky.
sec 50+tan 50=
=sec 50 - tan50 +2 tan50
=cosec 40 - cot 40 + 2tan50 (as cosec a=sec 90-a and so is with the other)
=(1/sin40)-(cos40/sin40) +2tan50
=(1-cos40)/sin40 +2tan50
you know that 1-cos2a=2sin^2a as cos 2a=1-2sin^2a
so 1-cos40=2sin^20
=[2sin^2 20/2sin20 cos20] +2tan50
=tan20 +2tan50
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