Question

sec 5A= cosec(A+30),where 5A is an acute angle,then the value of A is​

Answer 1

Answer :-

cosec(90 - 5A) = cosec(A-30)

90 - 5A = A - 30

90 + 30 = A + 5A

120 = 6A

A = 20

So, 5A = 5 × 20 = 100

Therefore, 5A is 100.

Answer 2

Answer:

cosec(A+30)= sec5A

sec(90-A-30)=sec5A. -(cosec thetha =sec 90-thetha)

so

sec(-A+60)=sec 5A

sec5A +sec A=sec60

sec6A=sec60

so

6A=60

A=10